Passing References to const

Why should I pass references to const when a function does not modify its arguments?

Passing references to const is a best practice in C++ for several reasons:

  1. It clearly communicates to other developers that the function will not modify the argument.
  2. It allows the function to accept both non-const and const arguments. If you don't use const, you can only pass non-const arguments.
  3. It can avoid unnecessary copying of large objects, which can improve performance.

Here's an example:

#include <iostream>

struct Vector {
  float x;
  float y;
  float z;
};

void PrintVector(const Vector& v) {
  std::cout << "Vector: (" << v.x << ", "
    << v.y << ", " << v.z << ")\n";
}

int main() {
  const Vector v1{1, 2, 3};
  Vector v2{4, 5, 6};

  PrintVector(v1);  // Okay, v1 is const
  PrintVector(v2);  // Also okay, v2 is non-const
}
Vector: (1, 2, 3)
Vector: (4, 5, 6)

If PrintVector didn't use const, it couldn't accept v1 as an argument.

Understanding Reference and Pointer Types

Learn the fundamentals of references, pointers, and the const keyword in C++ programming.

Questions & Answers

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