constexpr
and Dynamic Memory
What happens if I try to use dynamic memory allocation in a constexpr
function?
When you try to use dynamic memory allocation in a constexpr
function, you'll run into limitations. constexpr
functions are designed to be evaluated at compile-time, and dynamic memory allocation is inherently a runtime operation. Let's break this down:
Basic Rule
In general, you cannot use dynamic memory allocation (like new
, delete
, malloc()
, free()
) in constexpr
functions. This includes standard library functions that might use dynamic allocation internally, such as std::vector
or std::string
.
#include <iostream>
constexpr int* create_array(int size) {
// This will compile, but not allowed in
// a constant expression context
return new int[size];
}
int main() {
// This will cause a compile-time error
constexpr int* arr = create_array(5);
}
error: expression did not evaluate to a constant
note: (sub-)object points to memory which was heap allocated during constant evaluation
Compile-Time Error
If you try to use dynamic allocation in a constexpr
function, you'll get a compile-time error. The exact error message may vary depending on your compiler, but it will generally indicate that the operation is not allowed in a constant expression.
#include <iostream>
#include <string>
constexpr std::string get_greeting() {
// Will not compile in a constant expression context
return std::string("Hello");
}
int main() {
// This will cause a compile-time error
constexpr auto greeting = get_greeting();
std::cout << greeting << std::endl;
}
error: expression did not evaluate to a constant
note: (sub-)object points to memory which was heap allocated during constant evaluation
Alternatives
Instead of dynamic allocation, you can use fixed-size arrays or other compile-time data structures. For example:
#include <array>
#include <iostream>
constexpr std::array<int, 5> create_array() {
return {1, 2, 3, 4, 5};
}
int main() {
constexpr auto arr = create_array();
for (int i : arr) {
std::cout << i << ' ';
}
}
1 2 3 4 5
C++20 and Beyond
C++20 introduces constexpr
versions of some standard library components, including std::vector
and std::string
.
However, these still don't use actual dynamic allocation at compile-time. Instead, they use a special allocator that simulates dynamic allocation within fixed-size memory blocks.
This code will work in C++20 with a supporting compiler and standard library implementation.
#include <algorithm>
#include <iostream>
#include <vector>
constexpr int get_number() {
std::vector<int> vec = {3, 1, 2};
std::sort(vec.begin(), vec.end());
return vec.back();
}
int main() {
constexpr int num = get_number();
std::cout << "Number: " << num;
}
Number: 3
Remember, the goal of constexpr
is to enable compile-time computation. While recent C++ standards have expanded what's possible in constant expressions, they still maintain a clear distinction between compile-time and runtime operations.
When writing constexpr
functions, focus on algorithms and computations that don't require runtime resources or side effects.
Compile-Time Evaluation
Learn how to implement functionality at compile-time using constexpr
and consteval