Handling exceptions in constexpr
and consteval
functions is a bit tricky because these functions are designed for compile-time evaluation. Let's explore the rules and best practices:
constexpr
functions were not allowed to throw exceptions.constexpr
functions can throw exceptions, but only during runtime execution.consteval
functions (introduced in C++20) cannot throw exceptions at all.constexpr
FunctionsIn C++20, you can use try-catch blocks in constexpr
functions, but they will only have an effect during runtime execution:
#include <iostream>
#include <stdexcept>
constexpr int divide(int a, int b) {
if (b == 0) {
throw std::runtime_error("Division by zero");
}
return a / b;
}
int main() {
constexpr int result1 = divide(10, 2);
std::cout << "Result1: " << result1 << '\n';
try {
// Runtime error that will be caught:
int result2 = divide(10, 0);
std::cout << "Result2: " << result2 << '\n';
} catch (const std::exception& e) {
std::cout << "Caught exception: "
<< e.what() << '\n';
}
// This would cause a compile-time error:
// constexpr int result3 = divide(10, 0);
}
Result1: 5
Caught exception: Division by zero
For true compile-time error handling, you should use techniques that result in compilation failures rather than runtime exceptions:
#include <iostream>
#include <type_traits>
template <int A, int B>
struct SafeDivide {
static_assert(B != 0, "Division by zero");
static constexpr int value = A / B;
};
int main() {
constexpr int result1 = SafeDivide<10, 2>::value;
std::cout << "Result1: " << result1 << '\n';
// This would cause a compile-time error:
// constexpr int result2 = SafeDivide<10, 0>;
}
Result1: 5
std::is_constant_evaluated()
You can use std::is_constant_evaluated()
to have different behavior at compile-time and runtime:
#include <iostream>
#include <stdexcept>
#include <type_traits>
constexpr int safeDivide(int a, int b) {
if (std::is_constant_evaluated()) {
// Avoid exception at compile-time
return b != 0 ? a / b : 0;
} else {
if (b == 0) {
throw std::runtime_error("Division by zero");
}
return a / b;
}
}
int main() {
constexpr int result1 = safeDivide(10, 2);
std::cout << "Result1: " << result1 << '\n';
// This is 0, not an error
constexpr int result2 = safeDivide(10, 0);
std::cout << "Result2: " << result2 << '\n';
try {
// This throws at runtime
int result3 = safeDivide(10, 0);
std::cout << "Result3: " << result3 << '\n';
} catch (const std::exception& e) {
std::cout << "Caught exception: " << e.what();
}
}
Result1: 5
Result2: 0
Caught exception: Division by zero
consteval
FunctionsRemember, consteval
functions must be evaluated at compile-time and cannot throw exceptions:
consteval int alwaysCompileTime(int x) {
// This function can't use try-catch
// or throw exceptions
return x * 2;
}
In summary, while C++20 allows exceptions in constexpr
functions during runtime, it's often better to design your compile-time code to avoid exceptions altogether.
Use techniques like static assertions, SFINAE, or compile-time if-constexpr statements to handle errors at compile-time. For consteval
functions, focus on designs that don't require exception handling.
Answers to questions are automatically generated and may not have been reviewed.
Learn how to implement functionality at compile-time using constexpr
and consteval