When you have a function that takes multiple arguments of different types and you want to perfectly forward them to another function, you can use std::forward()
with a variadic template.
Here's an example:
#include <iostream>
#include <string>
#include <utility>
void process_data(int id,
const std::string& name, double value) {
std::cout
<< "ID: " << id
<< ", Name: " << name
<< ", Value: " << value << "\n";
}
template <typename... Args>
void forward_data(Args&&... args) {
process_data(std::forward<Args>(args)...);
}
int main() {
int id = 42;
std::string name = "John";
double value = 3.14;
forward_data(
id, name, value);
forward_data(
std::move(id), name, std::move(value));
}
ID: 42, Name: John, Value: 3.14
ID: 42, Name: John, Value: 3.14
In this example, forward_data()
is a variadic template function that takes any number of arguments of different types. It forwards these arguments to process_data()
using std::forward<Args>(args)...
, which expands the parameter pack args
and applies std::forward()
to each argument.
By using std::forward<Args>(args)...
, each argument is perfectly forwarded to process_data()
, preserving its value category (lvalue or rvalue) and const-ness.
In the main()
function, forward_data()
is called twice:
forward_data(id, name, value)
: Forwards id
, name
, and value
 as lvalues.forward_data(std::move(id), name, std::move(value))
: Forwards id
 and value
 as rvalues using std::move()
, while name
 is forwarded as an lvalue.This demonstrates how std::forward()
can be used with a variadic template to perfectly forward multiple arguments of different types, preserving their value categories and const-ness.
Answers to questions are automatically generated and may not have been reviewed.
std::forward
An introduction to problems that can arise when our functions forward their parameters to other functions, and how we can solve those problems with std::forward