std::views::filter()
and std::remove_if()
serve different purposes and have different performance characteristics.
std::views::filter()
has the following characteristics:
The following program uses std::views::filter()
to create a view of an underlying std::vector
. The view contains only the odd numbers within the vector, but the vector itself is not modified:
#include <iostream>
#include <ranges>
#include <vector>
int main() {
std::vector<int> Numbers{1, 2, 3, 4, 5};
auto FilteredView = Numbers
| std::views::filter([](int x) {
return x % 2 == 1;
});
for (int Num : FilteredView) {
std::cout << Num << ", ";
}
}
1, 3, 5,
std::remove_if()
has these characteristics:
The following program uses std::remove_if()
to move the even numbers to the end of a std::vector
.
It then uses the erase()
method to remove those elements from the container.
As a result, only the odd numbers remain in our std::vector
:
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
std::vector<int> Numbers{1, 2, 3, 4, 5};
auto it = std::remove_if(
Numbers.begin(), Numbers.end(),
[](int x) { return x % 2 == 0; }
);
Numbers.erase(it, Numbers.end());
for (int Num : Numbers) {
std::cout << Num << ", ";
}
}
1, 3, 5,
std::views::filter()
uses less memory since it doesn’t create a new container but instead provides a view. std::remove_if()
may require extra memory if elements are erased and the container is resized.std::views::filter()
can be faster for partial processing due to lazy evaluation. std::remove_if()
processes all elements eagerly, which may be less efficient for large datasets.std::views::filter()
when you need a non-modifying, lazy-evaluated view. Use std::remove_if()
when you need to modify the container directly and remove elements.Understanding these differences helps choose the right tool for specific use cases, balancing performance and functionality needs.
Answers to questions are automatically generated and may not have been reviewed.
Learn how to create and use views in C++ using examples from std::views