Implementing a type-safe enum pattern using type aliases in C++ is an interesting technique that can provide additional type safety and functionality compared to traditional enums.
This pattern is particularly useful when you want to create strongly-typed enumerations with custom behavior. Let's explore how to implement this pattern step by step.
Here's a basic implementation of a type-safe enum pattern using type aliases:
#include <iostream>
class Color {
public:
class ColorType {
friend class Color;
ColorType() = default;
public:
bool operator==(const ColorType&) const
= default;
};
static const ColorType Red;
static const ColorType Green;
static const ColorType Blue;
using Type = const ColorType&;
private:
Type m_value;
public:
constexpr Color(Type value)
: m_value(value) {}
constexpr operator Type() const {
return m_value;
}
};
const Color::ColorType Color::Red{};
const Color::ColorType Color::Green{};
const Color::ColorType Color::Blue{};
int main() {
Color c = Color::Red;
if (c == Color::Red) {
std::cout << "The color is red!\n";
}
}
The color is red!
In this implementation:
Color
class with a nested ColorType
class.using Type = const ColorType&;
to create an alias for our enum type.Color
class wraps the Type
and provides implicit conversion to Type
.We can extend this pattern to add functionality to our enum:
#include <iostream>
#include <string>
class Color {
class ColorType {
friend class Color;
std::string m_name;
explicit ColorType(const std::string& name)
: m_name(name) {}
public:
bool operator==(const ColorType&) const
= default;
const std::string& name() const {
return m_name;
}
};
public:
static const ColorType Red;
static const ColorType Green;
static const ColorType Blue;
using Type = const ColorType&;
private:
Type m_value;
public:
constexpr Color(Type value) : m_value(value) {}
constexpr operator Type() const {
return m_value;
}
const std::string& name() const {
return m_value.name();
}
};
const Color::ColorType Color::Red{"Red"};
const Color::ColorType Color::Green{"Green"};
const Color::ColorType Color::Blue{"Blue"};
int main() {
Color c = Color::Green;
std::cout << "The color is " << c.name();
}
The color is Green
This version adds a name()
method to our enum values, allowing us to get a string representation of each color.
This pattern provides strong type safety. For example:
#include <iostream>
class Color {
class ColorType {
friend class Color;
ColorType() = default;
public:
bool operator==(const ColorType&) const
= default;
};
public:
static const ColorType Red;
static const ColorType Green;
static const ColorType Blue;
using Type = const ColorType&;
private:
Type m_value;
public:
constexpr Color(Type value)
: m_value(value) {}
constexpr operator Type() const {
return m_value;
}
};
const Color::ColorType Color::Red{};
const Color::ColorType Color::Green{};
const Color::ColorType Color::Blue{};
class Shape {
public:
class ShapeType {
friend class Shape;
ShapeType() = default;
public:
bool operator==(const ShapeType&) const
= default;
};
static const ShapeType Circle;
static const ShapeType Square;
using Type = const ShapeType&;
private:
Type m_value;
public:
constexpr Shape(Type value)
: m_value(value) {}
constexpr operator Type() const {
return m_value;
}
};
const Shape::ShapeType Shape::Circle{};
const Shape::ShapeType Shape::Square{};
int main() {
Color c = Color::Red;
Shape s = Shape::Circle;
// This will not compile
if (c == s) {}
// This will not compile either
Color wrongColor = Shape::Circle;
// But this is fine
if (c == Color::Red) {
std::cout << "The color is red!";
}
}
error: binary '==': 'Color' does not define this operator
error: initializing: cannot convert from 'const Shape::ShapeType' to 'Color'
In this example, we can't compare a Color
to a Shape
, or assign a Shape
value to a Color
variable. This level of type safety is not possible with traditional C++Â enums.
Using type aliases to implement a type-safe enum pattern in C++ provides several benefits:
This pattern is particularly useful in large codebases where type safety is crucial, or when you need enums with custom behavior.
However, it does come with some overhead in terms of code complexity and potential runtime cost compared to traditional enums.
As with any pattern, consider the trade-offs for your specific use case before implementing it.
Answers to questions are automatically generated and may not have been reviewed.
Learn how to use type aliases, using
statements, and typedef
to simplify or rename complex C++ types.