In C++, a class can befriend itself, though it is not a common practice and typically not necessary.
Declaring a class as its own friend doesn't provide any additional access or capabilities because the class already has access to its own private and protected members.
Here’s how you would declare a class as its own friend:
class SelfFriend {
friend class SelfFriend;
private:
int value{42};
public:
int getValue() const { return value; }
};
In this example, SelfFriend
is declared as a friend of itself. However, this declaration does not change the access level of value
since SelfFriend
already has access to all its members.
Here’s an example with template specializations:
#include <iostream>
template <typename T>
class Container {
friend class Container<int>;
private:
T data;
public:
Container(T val) : data{val} {}
T getData() const { return data; }
};
template <>
class Container<int> {
friend class Container<double>;
private:
int data;
public:
Container(int val) : data{val} {}
int getData() const { return data; }
};
int main() {
Container<int> intContainer{100};
std::cout << intContainer.getData() << "\n";
Container<double> doubleContainer{3.14};
std::cout << doubleContainer.getData() << "\n";
}
100
3.14
In this example, the Container<int>
specialization befriends Container<double>
, allowing Container<double>
to access private members of Container<int>
.
This can be useful in specialized template classes where different instantiations need access to each other's internals.
While befriending itself is rarely necessary, it can be useful in certain advanced scenarios like template specializations or complex inheritance hierarchies.
However, for most practical purposes, a class does not need to befriend itself since it inherently has access to its own members.
Answers to questions are automatically generated and may not have been reviewed.
An introduction to the friend
keyword, which allows classes to give other objects and functions enhanced access to its members