Yes, you can use a functional-style requires
expression within your concept to specify that a class has a method with a certain signature. Here's an example:
#include <concepts>
template <typename T>
concept Renderable =
requires(T obj, int x, int y) {
{ obj.Render(x, y) } -> std::same_as<void>;
};
struct Sprite {
void Render(int x, int y);
};
static_assert(Renderable<Sprite>); // Passes
The Renderable
concept requires that for a type T
, it must have a member function Render
that is callable with two int
arguments x
and y
, and returns void
.
The requires
expression provides a way to describe the expected function signature. The obj
parameter represents an instance of type T
, and x
and y
serve as the arguments to the Render
 function.
The return type requirement { obj.Render(x, y) } -> std::same_as<void>
specifies that invoking Render
with x
and y
should return something of type void
.
If the Sprite
class meets these requirements (which it does in this case), the static_assert
will pass. If Sprite::Render
had a different signature, a compile error would occur.
Answers to questions are automatically generated and may not have been reviewed.
Learn how to use concepts to express constraints on classes, ensuring they have particular members, methods, and operators.